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This Is going to be Mind boggggggggggggGling !

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Tuesday, November 24, 2009

Assume that a restaurant has N dishes on its menu that are rated from worst to best, 1 to N (according to your personal preferences). You, however, don't know the ratings of the dishes, and when you try a new dish, all you learn is whether it is the best (highest rated) dish you have tried so far, or not. Each time you eat a meal at the restaurant you either order a new dish or you order the best dish you have tried so far. Your goal is to maximize the average total ratings of the dishes you eat in M meals (where M is less than or equal to N).

The average total ratings in a sequence of meals that includes n "new" dishes and b "best so far" dishes can be no higher than the average total ratings in the sequence having all n "new" dishes followed by all b "best so far" dishes. Thus a successful strategy requires you to order some number of new dishes and thereafter only order the best dish so far. The problem then reduces to the following:

Given N (dishes on the menu) and M <= N (meals to be eaten at the restaurant), how many new dishes D should you try before switching to ordering the best of them for all the remaining (M–D) meals, in order to maximize the average total ratings of the dishes consumed?

Solve it
Find D !
Answer in de next post !
i m BAK
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ScienTOON

2 comments

Tuesday, August 25, 2009

Cartoons are de best way to convey any message ! here i convey science
                 
 
 
 
 
 
                         
 
 
                                                                               




 
 

 
they r interesting ! Arent they ! 
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